P is a prime number greater than 3. The remainder of P² dividee by 24 must be.....?
Please solve it...and give a optimum solution.
- Aditya
- 04 Sep
- 11 Answers
11 Answers
11 Answers
-
10Modal content
-
10Modal content
-
1-1Modal content
-
10Modal content
-
1. In such cases, try to take 2-3 values and solve. and mark the option.0Modal content
-
digit sum of any perfect square is 14970&divisibility rule of 3 is sum of digits should be divisible by 3 when a digit sum ofsquare of any prime number divided by 3 you get reminder 11Modal content
-
10Modal content
-
prime numbers greater than 3 are always of the form of 6k+1 or 6k-1. put this in place of p. u will get 1 as remainder always2Modal content
-
10Modal content
-
answer will be 1. let's say a prime no 5 (>3) 5^2=25 25/24=1 (remainder) if we take 7(>3) 7^2=49 49/24=1( 49- 2*24= 49- 48=1 remainder)6Modal content
- sanskar
- deep
- amit
- dheeraj
- rahul
- pratyay
- sanskar
- deep
- amit
- dheeraj
- rahul
- pratyay
- No Down Vote
View all vote's
Other Related Discussions
-
Tell me some TIPS AND TRICKS of CAT
-
will I get good b.school.
-
I am a cat aspirant.i have got 91+ scores in 10 th and +2 and currently doing my graduation in maths. and i really want to get into iimA. so do i have a chance of getting it ,if not what should i do
-
I want to practice quant chapters till August before attempting sectionals n mocks. Is this the right stategy? Or, Am I wrong? Pls guide me!
-
how can i crack cat exam my own efforts?
-
how I can get mock tests?
-
What is CAT exam and eligibility?
-
I have my graduation by distance education. .. Does it really matters to get admission into iims or bschools
-
How can i solve the DI questions quickly?
-
Buy rare seeds
