A rope 1 cm in diameter breaks if tension in it exceeds 500 N. The maximum tension that may be given to a similar rope of diameter 2 cm is
A) 2000 N B) 1000 N C) 500 N D) 250 N
-
- 9834 Views
- 97 Answers
97 Answers
-
-
Sweety
- 14 Mar
- 1 Comment
-
-
The answer is A) 2000N Because, This is a question of young modulus and it's formula is - young modulus = (tension*original length)/(cross sectional area*change in length). From the question, we can say that all the quantities except tension and area are constant we can say that tension is directly proportion to area of cros section . thus tension is directly proportion to D²(as area = πD²/4; D is diameter). so if for D = 1 tension=500N then for D =2 tension will be four time i.e. tension=2000N
-
Prashant
- 01 Jun
- 0 Comment
-
- Maths section no new questions, kindly advise
- how many marks required to get the admission
- what are the imp certificates required for admission for engineering after 12th?
- Is this app for b.ed cet?
- minimum marks required to eligible for the admission in engineering
- questions are repeated
- is there any difference between home students and other state students?
- list of the document required for the obc candidate
- How can i get past 10yrs question papers of cet...?
- Which book will be best for questions for mhcet?
Practice Mock Test
mht cet
T = mrw2br /T a rbr /T2/T1 = r2/r1 = T2 = T1 * 2r1 / r1br /= 1000 N