A rope 1 cm in diameter breaks if tension in it exceeds 500 N. The maximum tension that may be given to a similar rope of diameter 2 cm is
A) 2000 N B) 1000 N C) 500 N D) 250 N
- Deepshikha
- 14 Mar
- 97 Answers
97 Answers
97 Answers
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B0Modal content
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2000N1Modal content
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Tension =2000N Becz D=2 tension wl b 4 times-1Modal content
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500-1Modal content
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Good0Modal content
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as you know that young's modulus = (tension*original length)/(cross sectional area*change in length) since in this question all the quantities except tension and area are constant we can say that tension∝area of cross section. thus tension∝D² (as area = πD²/4 ; D is diameter) so if for D =1 tension = 500N then for D = 2 tension will be four times i.e tension = 2000N.0Modal content
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1000 N0Modal content
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1000N0Modal content
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10000Modal content
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as b.s=plg. t1/t2=l1/l2. 500/t2=1/2. t2=1000.0Modal content
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2000 breaking force(Tmax)=pressure x area hence,Tmax is proportional to r^2 which is square of cross sectional radius-1Modal content
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2000 N bcoz 500÷0.5^2=f÷1^2-1Modal content
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1000 because diameter double tension also double-2Modal content
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provide more information-1Modal content
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