A rope 1 cm in diameter breaks if tension in it exceeds 500 N. The maximum tension that may be given to a similar rope of diameter 2 cm is

A) 2000 N B) 1000 N C) 500 N D) 250 N

Deepshikha
14 मार्च
97 उत्तर

97 उत्तर

- Sweety
- 14 मार्च
T = mrw2
T a r
T2/T1 = r2/r1 = T2 = T1 * 2r1 / r1
= 1000 N
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archit

smit

ranjan

jeslyn

mwape

bernard

mohit

midhun

shivani

kaviraj.a

archit

smit

ranjan

jeslyn

bernard

mohit

midhun

kaviraj.a

mwape

shivani
- Sher
- 29 जुलाई
1000
- 0 टिप्पणी
0

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- PD
  
  PRITISH
- 24 जुलाई
ratio of areas
(tension prop. to area)
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- AB
  
  Archit
- 23 जून
2000
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0

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- AA
  
  Aditya
- 23 जून
1000
- 0 टिप्पणी
0

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- AS
  
  Anzalnagohar
- 12 जून
B
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0

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- MS
  
  M
- 07 जून
B) 1000
- 0 टिप्पणी
0

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- AU
  
  Anjali
- 06 जून
B) 1000N
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0

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- SM
  
  Sharmila
- 05 जून
2000
- 0 टिप्पणी
0

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- Jayesh
- 05 जून
1000
- 0 टिप्पणी
0

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- RM
  
  Rituraj
- 04 जून
2000
- 0 टिप्पणी
0

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- Apurva
- 03 जून
1000N
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0

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- DC
  
  Dhivakar
- 03 जून
1000
- 0 टिप्पणी
0

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- SG
  
  Sarvesh
- 03 जून
1000
- 1 टिप्पणी
0

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- Auti
- 01 जून
1000
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- Prashant
- 01 जून
The answer is A) 2000N Because, This is a question of young modulus and it's formula is - young modulus = (tension*original length)/(cross sectional area*change in length). From the question, we can say that all the quantities except tension and area are constant we can say that tension is directly proportion to area of cros section . thus tension is directly proportion to D²(as area = πD²/4; D is diameter). so if for D = 1 tension=500N then for D =2 tension will be four time i.e. tension=2000N
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- BA
  
  Bernard
- 01 जून
F1*(d2)^2=F2*(d1)^2 F2=[500*(0.02)^2]÷[(0.01)^2] F2=2000Newtons
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- Abhishek
- 31 मई
B) 1000N
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- Midhun
- 31 मई
1000
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0

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- Atul
- 31 मई
1000N
- 0 टिप्पणी
0

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