from a cross AABb and aaBb the genotypes AABB: AaBB: AaBb:Aabb will be obtained in the ratio of 1) 1:1:1:1 2) 0:1:2:1 3) 0:1:2:0 4) 1:2:2:4 need answer with the crct explanation(punnet square diag)
neet as.
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option 2 is crct. 0:1:2:1 because from AABb we got four gametes AB AB Ab Ab , and similarly from aaBb we got four gametes aB aB ab ab and then if we do a cross between this gametes by using punnet square we get 0(zero) -number of AABB individuals, 4 - AaBB , 8 - AaBb , and 4 - Aabb individuals respectively. then by simplifying this we get the ratio 0:1:2:1. thank u. if u hv any prblm related to this ques. feel free to ask me ABHIK TAH email- abhiktah02@gmail.com
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