25 persons are in a room 15 of them play hockey..................
25 persons are in a room 15 of them play hockey, 17 of them play football and 10 of them play hockey and football. Then the number of persons playing neither hockey nor football is (A) 2 (B) 17 (C) 13 (D) 3
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The answer will be three (D)br /Thsi can be calculated bet using br /P(AUB)=P(A)+P(B)-P(A intersection B)br /which will give the answer as 3
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D) 3br /the total people are 25br /the people play hockey is 15br /the people play foot ball is 17 br /both are 10 people br /that means the people play only hockey is 15-10=5br /and football is 17-10=7br /sum all the individuals and combined players gives 22br /that means the remaining 3 will not play either of the games
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- Quantitative Aptitude
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