SBI JA and JAA exam question
The area of triangle is half the area of square. the perimeter of the square is the 224 cms. what is the area of the triangle? A) 1856cm sq. B) 1658cm sq. C) 1558cm sq. D) 1586cm sq. E) None of these
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- 25 May
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!--[if gte mso 9]xml w:WordDocument w:ViewNormal/w:View w:Zoom0/w:Zoom w:TrackMoves/ w:TrackFormatting/ w:PunctuationKerning/ w:ValidateAgainstSchemas/ w:SaveIfXMLInvalidfalse/w:SaveIfXMLInvalid w:IgnoreMixedContentfalse/w:IgnoreMixedContent w:AlwaysShowPlaceholderTextfalse/w:AlwaysShowPlaceholderText w:DoNotPromoteQF/ w:LidThemeOtherEN-US/w:LidThemeOther w:LidThemeAsianX-NONE/w:LidThemeAsian w:LidThemeComplexScriptX-NONE/w:LidThemeComplexScript w:Compatibility w:BreakWrappedTables/ w:SnapToGridInCell/ w:WrapTextWithPunct/ w:UseAsianBreakRules/ w:DontGrowAutofit/ w:SplitPgBreakAndParaMark/ w:DontVertAlignCellWithSp/ w:DontBreakConstrainedForcedTables/ w:DontVertAlignInTxbx/ w:Word11KerningPairs/ w:CachedColBalance/ /w:Compatibility w:BrowserLevelMicrosoftInternetExplorer4/w:BrowserLevel m:mathPr m:mathFont m:val="Cambria Math"/ m:brkBin m:val="before"/ m:brkBinSub m:val="--"/ m:smallFrac m:val="off"/ m:dispDef/ m:lMargin m:val="0"/ m:rMargin m:val="0"/ m:defJc m:val="centerGroup"/ m:wrapIndent m:val="1440"/ m:intLim m:val="subSup"/ m:naryLim m:val="undOvr"/ /m:mathPr/w:WordDocument /xml![endif]--!--[if gte mso 9]xml w:WordDocument w:ViewNormal/w:View w:Zoom0/w:Zoom w:TrackMoves/ w:TrackFormatting/ w:PunctuationKerning/ w:ValidateAgainstSchemas/ w:SaveIfXMLInvalidfalse/w:SaveIfXMLInvalid w:IgnoreMixedContentfalse/w:IgnoreMixedContent w:AlwaysShowPlaceholderTextfalse/w:AlwaysShowPlaceholderText w:DoNotPromoteQF/ w:LidThemeOtherEN-US/w:LidThemeOther w:LidThemeAsianX-NONE/w:LidThemeAsian w:LidThemeComplexScriptX-NONE/w:LidThemeComplexScript w:Compatibility w:BreakWrappedTables/ w:SnapToGridInCell/ w:WrapTextWithPunct/ w:UseAsianBreakRules/ w:DontGrowAutofit/ w:SplitPgBreakAndParaMark/ w:DontVertAlignCellWithSp/ w:DontBreakConstrainedForcedTables/ w:DontVertAlignInTxbx/ w:Word11KerningPairs/ w:CachedColBalance/ /w:Compatibility w:BrowserLevelMicrosoftInternetExplorer4/w:BrowserLevel m:mathPr m:mathFont m:val="Cambria Math"/ m:brkBin m:val="before"/ m:brkBinSub m:val="--"/ m:smallFrac m:val="off"/ m:dispDef/ m:lMargin m:val="0"/ m:rMargin m:val="0"/ m:defJc m:val="centerGroup"/ m:wrapIndent m:val="1440"/ m:intLim m:val="subSup"/ m:naryLim m:val="undOvr"/ /m:mathPr/w:WordDocument /xml![endif]--br /Find the length of the sides of the sq., sbr /Area of sq. = s^2br /etcbr /br /Perimeter of square = 4s, thereforebr /4s = 224 andbr /br /s = 56br /now space of sq. = s^2 = 56^2 = 3136 andbr /area of triangle = 3136 / a pair of = 1586 cm^2br /!--[if gte mso 9]xml w:LatentStyles DefLockedState="false" DefUnhideWhenUsed="true" DefSemiHidden="true" DefQFormat="false" DefPriority="99" LatentStyleCount="267" w:LsdException Locked="false" Priority="0" SemiHidden="false" UnhideWhenUsed="false" QFormat="true" Name="Normal"/ w:LsdException Locked="false" Priority="9" SemiHidden="false" UnhideWhenUsed="false" QFormat="true" Name="heading 1"/ w:LsdException Locked="false" Priority="9" QFormat="true" Name="heading 2"/ w:LsdException Locked="false" Priority="9" QFormat="true" Name="heading 3"/ w:LsdException Locked="false" Priority="9" QFormat="true" Name="heading 4"/ w:LsdException Locked="false" Priority="9" QFormat="true" Name="heading 5"/ w:LsdException Locked="false" Priority="9" QFormat="true" Name="heading 6"/ w:LsdException Locked="false" Priority="9" QFormat="true" Name="heading 7"/ w:LsdException Locked="false" Priority="9" QFormat="true" Name="heading 8"/
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- 16 May
- 1 Comment
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- explain d questions so dat i know how to solve it
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