A rope 1 cm in diameter breaks if tension in it exceeds 500 N. The maximum tension that may be given to a similar rope of diameter 2 cm is

A) 2000 N B) 1000 N C) 500 N D) 250 N

97 答案

B
- Deepika
- 29 3月
- 0 评论
0
2000N
- Arpan
- 24 2月
- 0 评论
1
Tension =2000N Becz D=2 tension wl b 4 times
- Megha
- 14 2月
- 0 评论
-1
👶💜✌
- Ajaib
- 06 2月
- 0 评论
1
500
- Priyanka
- 03 2月
- 0 评论
-1
Good
- Yagpal
- 02 12月
- 1 评论
0
as you know that young's modulus = (tension*original length)/(cross sectional area*change in length) since in this question all the quantities except tension and area are constant we can say that tension∝area of cross section. thus tension∝D² (as area = πD²/4 ; D is diameter) so if for D =1 tension = 500N then for D = 2 tension will be four times i.e tension = 2000N.
- Deepak
- 27 11月
- 1 评论
0
1000N
- Pathan
- 28 10月
- 0 评论
-1
1000 N
- Rishikesh
- 10 10月
- 0 评论
0
1000N
- Binawade
- 08 9月
- 0 评论
0
1000
- Sahil
- 09 5月
- 0 评论
0
as b.s=plg. t1/t2=l1/l2. 500/t2=1/2. t2=1000.
- Suraj
- 07 5月
- 0 评论
0
2000N
- Devansh
- 05 5月
- 0 评论
-1
500
- Will
- 03 5月
- 0 评论
-1
D) 250
- Kavita
- 23 4月
- 0 评论
-1
2000 breaking force(Tmax)=pressure x area hence,Tmax is proportional to r^2 which is square of cross sectional radius
- Amit
- 18 4月
- 0 评论
-1
2000 N bcoz 500÷0.5^2=f÷1^2
- Omeshwari
- 17 4月
- 0 评论
-1
A
- Siddharth
- 14 4月
- 0 评论
-1
1000 because diameter double tension also double
- Vikas
- 12 4月
- 0 评论
-2
provide more information
- Milind
- 09 4月
- 0 评论
-1

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