in induction motor the rotor input is 600W and slip is 4% the rotor copper loss is ???
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- Sunil
- 31 Jan
- 10 Answers
10 Answers
10 Answers
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Rotor copper loss = slip * rotor input i.e 600*(4/100)=24.2Modal content
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relation between input power:copper loss:output power=1:s:1-s by using this Pg/i2r=1/s we get answer as 24w1Modal content
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24 watts0Modal content
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24 watt0Modal content
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800Modal content
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24 watt3Modal content
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0.04*600= 24W0Modal content
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0.04*600=24watt0Modal content
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0-2Modal content
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