In a resonance column experiment first and second resonance occur at depths 22.7 cm and 70.2 cm respectively then depth at which third resonance occurs is_ A)117.7 cm B)102.2 C)122 cmc D)117.999 cm

(Consider end correction)

Your Answer

l1+e=lambda÷4,l2+e=3lambda÷4,l3+e=5lambda÷4. l1+e÷l2+e=1÷3;l1+e÷l3+e=1÷5. e=70.2-3*22.7÷2=1.05. l3+e=5(l1+e), l3=5(22.7+1.05)-1.05=117.7 so the ans is a

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