Difference between ++*p, *p++ and *++p

The pre and post increment with *, I am confused here. Is it pointer in the first two cases?

• Aditi
• 5941 Views
• 2 Answers

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  • Kane
  • 22 May
  • 0 Comment

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• The expression ++*p has two operators of same precedence, so compiler looks for assoiativity. Associativity of operators is right to left. Therefore the expression is treated as ++(*p). Therefore the output of first program is “arr[0] = 11, arr[1] = 20, *p = 11“.br /br /The expression *p++ is treated as *(p++) as the precedence of postfix ++ is higher than *. Therefore the output of second program is “arr[0] = 10, arr[1] = 20, *p = 20“.br /br /The expression *++p has two operators of same precedence, so compiler looks for assoiativity. Associativity of operators is right to left. Therefore the expression is treated as *(++p). Therefore the output of second program is “arr[0] = 10, arr[1] = 20, *p = 20“.

  • Archana
  • 02 Apr
  • 0 Comment

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