Problem Based on HCF and LCM(Aptitude)

Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. A. 4 B. 7 C. 9 D. 13

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  • Hi Nandhini!This is Neeraj Atluri.Simple way to answer these type of questions are:
    Consider 3 numbers A,B,C(A<B<C) such that leave same reminer when divided by a number .Find the number n=
    H.C.F{(A-B),(A-C),(B-C)}
    So by applying this formula we will get the answer =4;
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  • Answer   A)4
    Expalnation:

    Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
         = H.C.F. of 48, 92 and 140 = 4.
     
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