A shopkeeper professes to sell his goods at cost price. But he uses a false weight and thus gains 6+18/47% for a kg, he uses a weight of

options: (A) 940 gm (B) 947 gm (C) 953 gm (D) 960 gm

Love
19 Oct
5 Answers

5 Answers

- NY
  
  Nisha
- 19 Oct
To find the weight used by the shopkeeper, we can set up the following equation:
(X - W) / W = 6 + 18/47%
First, let's convert the percentage into a decimal:
6 + 18/47% = 6 + (18/47) * 0.01 = 6 + 0.0003829787 ≈ 6.0003829787
Now, we can rewrite the equation:
(X - W) / W = 6.0003829787
Cross-multiply:
X - W = 6.0003829787 * W
Now, let's solve for X:
X = W + 6.0003829787 * W X = 1 * W + 6.0003829787 * W X = 7.0003829787 * W

We need to find the weight that is approximately 7 times the actual weight (W). The weight closest to 7 times W is 940 grams, which is option (A).
So, the shopkeeper is using a weight of 940 grams.
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- MI
  
  Mubin
- 07 Apr
c
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  Umasai
- 06 Apr
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- PC
  
  Priya
- 21 Nov
someone please explain
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  Kalpesh
- 18 Oct
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