A sum was put at simple interest at certain rate for 2years.had it been put at 3%higher rate.It would have fetched Rs.72 more. The sum is
how to solve
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Shruti
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मॉक परीक्षण अभ्यास के लिए
cpt - common proficiency test
"Let the sum be Rs. x and original rate be R% . Then , ([x×(R+3)×2]/100) − ([x×R×2]/100) = 72 ⇔ 2Rx+6x−2Rx=7200 ⇔ 6x=7200 ⇔ x= 1200"