in rotating electrical machine,the chording angle for eliminating fifth harmonic should be 1 36 2 30 3 90

please tell me ans

Rajan
24 मई
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- PS
  
  Prahalad
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36
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5 110
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  Raja
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- AV
  
  Aluru
- 24 दिसम्बर
kpn-cosnE/2-0:here n-5 so finally E-36
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- SI
  
  Stephen
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  Radha
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  Jinna
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36 for 5th and 7th harmonics
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  Subham
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bobin

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  Shivam
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  Meeravali
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36°
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  Karthi
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  Rakesh
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- Shruti
- 20 जून
To eliminate 5th harmonic kp5 must be zero, kpn= cosnε/2 ⇒ kp5= cos5ε/2=0=cos90° ⇒ 5ε/2=90° ⇒ ε =36°.
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kusuma

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kusuma

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