to what angle a projectile must be projected so that area swept by it is maximum????
this question is of havards entrance which has a level much higher than jee. you will get the answer soon!!!
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answer is 45 degree ... based on my analysis.. it is the height the projectile is to reach is to be highest..br /br /Please tell me where u found this harward questions., I want to solve more of these ...
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see frnd its just a simple br /br /The relation between the range R br /?br / on the horizontal plane and the maximum height hbr /?br /reached at td/2br /?br / is:br /?br /h= R tan(tetha)/4br /br /Now , h = R , at tan (theta ) = 4br /Which gives angle as 76° ...br /
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