A rope 1 cm in diameter breaks if tension in it exceeds 500 N. The maximum tension that may be given to a similar rope of diameter 2 cm is

A) 2000 N B) 1000 N C) 500 N D) 250 N

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Your Answer

2000 breaking force(Tmax)=pressure x area hence,Tmax is proportional to r^2 which is square of cross sectional radius

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