Problem Based on HCF and LCM(Aptitude)

Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. A. 4 B. 7 C. 9 D. 13

• Jeyamari
• 2940 दृश्य
• 2 उत्तर

• Hi Nandhini!This is Neeraj Atluri.Simple way to answer these type of questions are:br /Consider 3 numbers A,B,C(A<B<C) such that leave same reminer when divided by a number .Find the number n=br /H.C.F{(A-B),(A-C),(B-C)}br /So by applying this formula we will get the answer =4;

  • Atluri
  • 08 जुलाई
  • 0 टिप्पणी

  0

  ---

• Answer   A)4br /Expalnation:br /br /Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)br /     = H.C.F. of 48, 92 and 140 = 4.br / 

  • Jeyamari
  • 06 जुलाई
  • 0 टिप्पणी

  0

  ---

• i am looking for a job bhot year ho gye job dhund rha hu koi to rakhlo job
• Insert the missing number in the given series
• Why should I bother paying for aptitude tests?
• Series
• य‍द‍ि ‍‍‍क‍िसी संखया के अंकाे का याेेेग 15 ‍है तथा उस संखया में 9 जोड दे तो
• what is Deferent between OLTC and OCTC
• Common Aptitude Questions for Competitive Exams
• General knowledge and current affairs
• Mixture and alligation
• Common aptitude questions on Time, speed and distance.