A shopkeeper professes to sell his goods at cost price. But he uses a false weight and thus gains 6+18/47% for a kg, he uses a weight of
options: (A) 940 gm (B) 947 gm (C) 953 gm (D) 960 gm
-
- 6619 दृश्य
- 5 उत्तर
5 उत्तर
- which month bsc magazine will be useful for ibps po
- when the price of fans was reduced by 20% the number of fans sold increased by 40%. what was the effect on the sales rupees ?
(1) 12% decrease
(2) 12% increase
(3) 40% increase
(4) 30% increase
- rrb officers scale-1 syllabus please
- Is there any percentage criteria for bank po?
- Please explain the eligibility criteria for IBPS PO 2018.
- What would be the cutoff mark to clear IBPS PO?
- A and B started his journey from the same place at the same time. B started with the speed of 5/6th the speed of A and reached the destination in 1 hr.15 minutes after A. How much time did B take to
- how many kg of salt at 42paise per kg mixed with another 25kg of salt at 24 paise per kg so that on selling the mixture at 40 paise per kg to gain 25%
- Can final year students apply for IBPS PO?
- I need an App that can help me with the preparations?
मॉक परीक्षण अभ्यास के लिए
ibps po prelim exam
To find the weight used by the shopkeeper, we can set up the following equation:br /(X - W) / W = 6 + 18/47%br /First, let's convert the percentage into a decimal:br /6 + 18/47% = 6 + (18/47) * 0.01 = 6 + 0.0003829787 ≈ 6.0003829787br /Now, we can rewrite the equation:br /(X - W) / W = 6.0003829787br /Cross-multiply:br /X - W = 6.0003829787 * Wbr /Now, let's solve for X:br /X = W + 6.0003829787 * W X = 1 * W + 6.0003829787 * W X = 7.0003829787 * Wbr /br /We need to find the weight that is approximately 7 times the actual weight (W). The weight closest to 7 times W is 940 grams, which is option (A).br /So, the shopkeeper is using a weight of 940 grams.