please send solving
a man start going for morning walk every day. the distance walked by him on the first day was 2 kms. everyday he walks half of the distance walked on the previous day. what can be maximum total distance? walked by him in his life time?
- Shubh
- 07 नवम्बर
- 11 उत्तर
11 उत्तर
11 उत्तर
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The man walks 2 kilometers on the first day, and then each subsequent day he walks half the distance of the previous day. This forms a geometric progression with the first term (a) as 2 and a common ratio (r) of 1/2.
The formula to find the sum of a geometric progression (S) is given by:
S = a / (1 - r)
In this case, a = 2 and r = 1/2. Let's calculate the maximum total distance walked in his lifetime:
S = 2 / (1 - 1/2)
S = 2 / (1/2)
S = 2 * 2
S = 4 kilometers0Modal content
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>40Modal content
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4km it is actually a geometric infinitive progression where the ratio is 0.5 and the first term is 2km. equation for infintive gp S= A/(1-r)0Modal content
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its a GP. solve by Sn formula. a/(1-r) here a is 2 and r is 1/2.0Modal content
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4 km0Modal content
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app. 4km.0Modal content
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3.750Modal content
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Approx 4km0Modal content
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4 km0Modal content
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4 km3Modal content
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44Modal content
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