P is a prime number greater than 3. The remainder of P² dividee by 24 must be.....?

Please solve it...and give a optimum solution.

11 उत्तर

1
- Sathish
- 04 सितम्बर
- 0 टिप्पणी
0
1
- Manmohan
- 02 सितम्बर
- 0 टिप्पणी
0
1
- Jitendra
- 29 अगस्त
- 0 टिप्पणी
-1
1
- Nidhi
- 21 अगस्त
- 0 टिप्पणी
-1
1
- Ekta
- 18 अगस्त
- 0 टिप्पणी
0
1. In such cases, try to take 2-3 values and solve. and mark the option.
- Sangram
- 17 अगस्त
- 0 टिप्पणी
0
digit sum of any perfect square is 14970&divisibility rule of 3 is sum of digits should be divisible by 3 when a digit sum ofsquare of any prime number divided by 3 you get reminder 1
- Venu
- 16 अगस्त
- 0 टिप्पणी
1
1
- Anaparthi
- 28 जून
- 0 टिप्पणी
0
prime numbers greater than 3 are always of the form of 6k+1 or 6k-1. put this in place of p. u will get 1 as remainder always
- Himanshu
- 28 जून
- 0 टिप्पणी
2
1
- Rahul
- 28 जून
- 0 टिप्पणी
0
answer will be 1. let's say a prime no 5 (3) 5^2=25 25/24=1 (remainder) if we take 7(3) 7^2=49 49/24=1( 49- 2*24= 49- 48=1 remainder)
- Vishal
- 27 जून
- 0 टिप्पणी
6

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