The difference between the circumference and the diameter of the circle is 15m.

What is the area of the circle?

• Deepshikha
• 4944 दृश्य
• 6 उत्तर

• !--[if !mso] style v\:* {behavior:url(#default#VML);} o\:* {behavior:url(#default#VML);} w\:* {behavior:url(#default#VML);} .shape {behavior:url(#default#VML);} /style ![endif]--!--[if gte mso 9]xml w:WordDocument w:ViewNormal/w:View w:Zoom0/w:Zoom w:TrackMoves/ w:TrackFormatting/ w:PunctuationKerning/ w:ValidateAgainstSchemas/ w:SaveIfXMLInvalidfalse/w:SaveIfXMLInvalid w:IgnoreMixedContentfalse/w:IgnoreMixedContent w:AlwaysShowPlaceholderTextfalse/w:AlwaysShowPlaceholderText w:DoNotPromoteQF/ w:LidThemeOtherEN-US/w:LidThemeOther w:LidThemeAsianX-NONE/w:LidThemeAsian w:LidThemeComplexScriptX-NONE/w:LidThemeComplexScript w:Compatibility w:BreakWrappedTables/ w:SnapToGridInCell/ w:WrapTextWithPunct/ w:UseAsianBreakRules/ w:DontGrowAutofit/ w:SplitPgBreakAndParaMark/ w:DontVertAlignCellWithSp/ w:DontBreakConstrainedForcedTables/ w:DontVertAlignInTxbx/ w:Word11KerningPairs/ w:CachedColBalance/ /w:Compatibility w:BrowserLevelMicrosoftInternetExplorer4/w:BrowserLevel m:mathPr m:mathFont m:val="Cambria Math"/ m:brkBin m:val="before"/ m:brkBinSub m:val="--"/ m:smallFrac m:val="off"/ m:dispDef/ m:lMargin m:val="0"/ m:rMargin m:val="0"/ m:defJc m:val="centerGroup"/ m:wrapIndent m:val="1440"/ m:intLim m:val="subSup"/ m:naryLim m:val="undOvr"/ /m:mathPr/w:WordDocument /xml![endif]--br /Answer will be Option (d)br /(2πr =2r) = 15br /r = 7/2br /πr2 = 22/7 x 7/2 x 7/2 = 38.5 m2br /!--[if gte mso 9]xml w:LatentStyles DefLockedState="false" DefUnhideWhenUsed="true" DefSemiHidden="true" DefQFormat="false" DefPriority="99" LatentStyleCount="267" w:LsdException Locked="false" Priority="0" SemiHidden="false" UnhideWhenUsed="false" QFormat="true" Name="Normal"/ w:LsdException Locked="false" Priority="9" SemiHidden="false" UnhideWhenUsed="false" QFormat="true" Name="heading 1"/ w:LsdException Locked="false" Priority="9" QFormat="true" Name="heading 2"/ w:LsdException Locked="false" Priority="9" QFormat="true" Name="heading 3"/ w:LsdException Locked="false" Priority="9" QFormat="true" Name="heading 4"/ w:LsdException Locked="false" Priority="9" QFormat="true" Name="heading 5"/ w:LsdException Locked="false" Priority="9" QFormat="true" Name="heading 6"/ w:LsdException Locked="false" Priority="9" QFormat="true" Name="heading 7"/ w:LsdException Locked="false" Priority="9" QFormat="true" Name="heading 8"/ w:LsdException Locked="false" Priority="9" QFormat="true" Name="heading 9"/ w:LsdException Locked="false" Priority="39" Name="toc 1"/ w:LsdException Locked="false" Priority="39" Name="toc 2"/ w:LsdException Locked="false" Priority="39" Name="toc 3"/ w:LsdException Locked="false" Priority="39" Name="toc 4"/ w:LsdException Locked="false" Priority="39" Name="toc 5"/ w:LsdException Locked="false" Priority="39" Name="toc 6"/ w:LsdException Locked="false" Priority="39" Name="toc 7"/ w:LsdException Locked="false" Priority="39" Name="toc 8"/ w:LsdException Locked="false" Priority="39" Name="toc 9"/ w:LsdException Locked="false" Priority="35" QFormat="true" Name="caption"/ w:LsdException Locked="false" Priority="10" SemiHidden="false" UnhideWhenUsed="false" QFormat="true" Name="Title"/ w:LsdException Locked="false" Priority="1" Name="Default Paragraph Font"/ w:LsdException Locked="false" Priority="11" SemiHidden="false" UnhideWhenUsed="false" QFormat="true" Name="Subtitle"/ w:LsdException Locked="false" Priority="22" SemiHidden="false" UnhideWhenUsed="false" QFormat="true" Name="Strong"/ w:LsdException Locked="false" Priority="20" SemiHidden="false" UnhideWhenUsed="false" QFormat="true" Name="Emphasis"/ w:LsdExcept--

  • Swati
  • 13 मार्च
  • 0 टिप्पणी

  4

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• 2πr =2r = 15br /r = 7/2br /πr2 = 22/7 x 7/2 x 7/2 = 38.5 m2br / div /div

  • Vaibhav
  • 20 जुलाई
  • 0 टिप्पणी

  0

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• Answer will be Option (d) (2πr =2r) = 15 r = 7/2 πr2 = 22/7 x 7/2 x 7/2 = 38.5 m2

  • Divya
  • 14 जुलाई
  • 0 टिप्पणी

  0

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• 2 * pi * r - 2 * r = 15br /r = 7/2br /pi * r * r = 38.5 m2 is the answer

  • Divyansh
  • 08 जुलाई
  • 0 टिप्पणी

  0

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• 2πr - 2r = 15br /r = 14/(2π - 2)br /r = 14*7/30br /AREA:br /πr^2 = (22*49*49)/(7*15*15)br /= 33.53

  • Abhishek
  • 08 जुलाई
  • 0 टिप्पणी

  0

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• The answer may be 40.6 cm^2

  • Ilham
  • 01 जुलाई
  • 0 टिप्पणी

  0

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