if the total energy of an electron in a hydrogen atom in an excited state is -3.4eV then what is the de-broglie wavelength of the electron

atomic structure

  • Sam
  • 09 जून
  • 8421 दृश्य
  • 2 उत्तर
Your Answer

2pi r = n wavelength .; here, r( radius of 2nd orbital)= 0.529× n^2 ;; r= 0.529 × 4 angstrom. ;; wavelenght = (2 × 3.14× 2.116)/2 answer =6.64 angstrom.

-1

  • MISCONCEPT

blue अन्य संबंधित चर्चाएं
aiims
मॉक परीक्षण अभ्यास के लिए
aiims
मॉक टेस्ट ले forward