Answer this question.
Q. How many 3-digit numbers will be there which are divisible by 19?
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Let's solve this problem without using any mathematical formula of Arithmetic Progression. This gives us the speedy answer which is so required in the competitive exams where there is a constraint of time.br /The greatest three digit number is 999.br /And 999/19 = 52.57.br /This implies upto 999, a total of 52 numbers are completely divisible.br /Subtracting from this, number of two- digit numbers also divisible by 19 taken into account in the previous calculation, i.e 19,38,57,76, and 95, we get :br /52-5 = 47 br /Thus there are 47 such 3 digit numbers in all.