Let A Denote the set of positive integers, each of them whrn divided bu 2,3,4,5 and 6 leaves the remainder of1,2,3,4 & 5 respectively. How many numbers in A are between 0 & 100

solve please

Your Answer

Since the difference between the divisor and the remainder in each case is 1. So the required number is given by = LCM(2,3,4,5,6) - 1 
= 60-1
= 59

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