kp for the reaction A->B is 4.If initially only A is present then what will be the partial pressure of B after equillibrium? a)1.2 b)0.8 c)0.6 d)1

plz give explanation

Your Answer

Kp=KcRT^n. n =0, hence Kp=Kc A------->B 1 O 1-x x There fore 4=x/1-x Hence x=0.8

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