A bullet of mass m travelling witb velocity v gets embedded into sand bag of mass M , suspended by a unstored cable string , the loss in kinetic energy in this process will be: 1. (m^2 × v^2)/2 (m+ M)

2. 1/2( M-m )v^2 3. 1/2 mv^2 4. (mM v^2)/2(m +M)

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does anyone know the answer?

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