if the total energy of an electron in a hydrogen atom in an excited state is -3.4eV then what is the de-broglie wavelength of the electron

atomic structure

  • Sam
  • 09 Jun
  • 8492 Views
  • 2 Answers
Your Answer

2×pie ×r = 2wavelength [ R= 0.529×4×10^-10 ] WAVELENGTH= 6.64×10^-10

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