A moving along a straight highway with speed of 126 km/h is brought to a stop within a distance of 200 m. What is the retardation of the car and how long does it take for the car to stop?

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Your Answer

u=126km/hr =35m/s now v=0 S=200m a=? t=? using v^2=u^2+2aS 0=(35)^2+2*a*200 a=-1225/400 a=-3.06m/s^2 also using v-u=at 0-35=-3.06t t=35/3.06s

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