when Tertbutylcarbamid react with KBrO the product is 'X' which then react with HNO2 gives tertiary butyle alcohol

(CH3)3C-CO-NH2. + KBrO-------->X X+HNO2------->(CH3)3C-OH

Your Answer

X=(CH3)3NH2 kobr is a reagent for Hoffman bromide reaction

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