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energy of h-atom in the ground state is -13.6 ev ,hence energy in the second excited state is 1)-3.4ev 2)6.4ev what is the ans explain it

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the answer is -3.4 as,E=Eo/n^2, where n=no. of hydrogen atoms i.e. 4 ,Eo=energy at ground state and E=energy at excited state

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