Mindtree question from quant section. Plz answer?

Qus. Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them? A. 42, 33 B. 42, 36 C. 44, 33 D. 44, 36

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  • Alternative trick is just check the option given 42-33=9 42-36=6 44-33=10 44-36=8 Answer is first option
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  • Answer is Option A 42,33
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  • Answer: Option A
    Explanation:
    Let the marks secured by them be xx and (x+9)(x+9)

    sum of their marks =x + (x+9)
     = 2x+9
    =x+(x+9)
    =2x+9

    Given that (x+9)(x+9) was 56% of the sum of their marks.
    ⇒(x+9)
    =56100(2x+9)⇒(x+9)=1425(2x+9)⇒25x+225=28x+126⇒3x=99⇒x=33⇒(x+9)=56100(2x+9)⇒(x+9)=1425(2x+9)⇒25x+225=28x+126⇒3x=99⇒x=33

    Then (x+9)=33+9=42(x+9)=33+9=42

    Hence their marks are 33 and 42
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