in rotating electrical machine,the chording angle for eliminating fifth harmonic should be 1 36 2 30 3 90

please tell me ans

• Rajan
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• 18 Answers

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  • Prahalad
  • 12 Jan
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  • Hitesh
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  • Raja
  • 23 Dec
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• kpn-cosnE/2-0:here n-5 so finally E-36

  • Aluru
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  • Pravanjan
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• 36 for 5th and 7th harmonics

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• 36°

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• To eliminate 5th harmonic kp5 must be zero, kpn= cosnε/2 ⇒ kp5= cos5ε/2=0=cos90° ⇒ 5ε/2=90° ⇒ ε =36°.

  • Shruti
  • 20 Jun
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