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The real number K for which the equation is, 2x3 + 3x + k = 0 has Two distinct real roots in {0,1}

Answer from the following options – (a) lies between 1 and 2 (b) lies between 2 and 3 (c) lies between -1 and 0 (d) does not exist

  • Surbhi
  • 15136 Views
  • 12 Answers
  Answer
12 Answers

  • If I remember correctly then this is a question of jee main 2013. As the others have answered the correct option is (d)

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  • D

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  • As the graph of this function is increasing function so it can never cut x axis as as a result no roots are possible so answer is d

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  • D

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  • d

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  • D

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  • As it is strictly increasing function ,no value of k exists .so and is (d)

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  • to goo kha

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  • The answer's d br / 

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  • ans. is d because if the roots are real then the parabola cuts the roots

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  • is it x^3 or 2*x*3

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  • Correct option will be (d)br /emf/em(emx/em) = 2emx/em3 + 3emx /em+ emkf/em′(emx/em) = 6emx/em2 + 3emf/em′(emx/em) = 0br /          ⇒ emx2 = -1/2/embr /          Not Possible.br /          As condition for two distinct real root is f(α) f(β) = 0br /         (where α, β are roots of f '(x) = 0 )

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