The real number K for which the equation is, 2x3 + 3x + k = 0 has Two distinct real roots in {0,1}
Answer from the following options – (a) lies between 1 and 2 (b) lies between 2 and 3 (c) lies between -1 and 0 (d) does not exist
- 15876 Views
- 12 Answers
12 Answers
-
-
- 16 Apr
- 0 Comment
-
-
As the graph of this function is increasing function so it can never cut x axis as as a result no roots are possible so answer is d
-
- 06 Mar
- 0 Comment
-
-
Correct option will be (d)br /emf/em(emx/em) = 2emx/em3 + 3emx /em+ emkf/em′(emx/em) = 6emx/em2 + 3emf/em′(emx/em) = 0br / ⇒ emx2 = -1/2/embr / Not Possible.br / As condition for two distinct real root is f(α) f(β) = 0br / (where α, β are roots of f '(x) = 0 )
-
- 08 Apr
- 0 Comment
-
- what is the meaningof ^
- anyone knows about byju classes?
are they good for physics to clear JEE mains exam?
- Need guidance for IIT-JEE in 4 months
- Mechanism, of free radical
- Find the period of the function f(x) =cos²3x+tan4x.
- in organic chemistry i am so confused in answers
- jee exam analysis
- How to understand the competition of JEE Mains ?
- what are the easy tricks to solve the problem in physics
- when will jee advanced 2018 exam conduct?
Practice Mock Test
jee main
If I remember correctly then this is a question of jee main 2013. As the others have answered the correct option is (d)