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The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:

A. 3 B. 4 C. 2 D. 1

  • Deepshikha
  • 37547 Views
  • 1730 Answers
  Answer
1730 Answers

  • 2

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  • 2

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  • 2

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  • 3

    -1

  • The answer is c)2br /    Given:br /         The product of two numbers is 2028.br /                i.e.  XY=2028br /         The prime factorisation of 2028 are 2,2,3,13,13.br /           The hcf of two number is 13.br /                X=13(A)          Y=13(B)br /           From the prime factorisation ,the combinations formed are br /                1)X=13(1)        Y=13(2*2*3)br /                 2)X=13(2)       Y=13(2*3)br /                 3)X=13(2*2)     Y=13(3)br /             1) AND 3) have the HCF 13.2)have HCF 26.br /strong             Hence there are totally 2 pairs available.(13,2028),(52,39)/strongbr /

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  • C

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  • B

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  • Option (c) 2

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  • 2

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  • Ans: 2-C

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  • C.2

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  • 2

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  • 26,13

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  • C:2

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  • 4

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  • C

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  • C

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  • C

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  • Answer : 2 (Option C)

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  • Answer: c

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