Aptitude question for Accenture

Ques. If v3 cot^2? - 4cot?+ v3 =0, then find the value of cot^2? + tan^2?

  • Anwar Khan Anwar
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  • Sol:br /Given √3 cot2θ - 4cotθ + √3 = 0.br /br /⇒ √3 Cot2θ - 3 Cot θ - Cot θ+ √3 = 0br /br /⇒ √3 Cot θ( Cot θ  - √3)  - 1( Cot θ - √3)  = 0br /br /⇒ ( Cot θ  - √3)(√3 Cot θ - 1) = 0br /br /Cot θ = √3  and  Cot θ = 1 / √3 .br /br /let Cot θ = √3 and Tan θ = 1 / √3 .br /br /Now Cot2θ +Tan2θ = 3 + 1 / 3 = 10 / 3.

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  • Given √3 cot2θ - 4cotθ + √3 = 0.br /br /⇒ √3 Cot2θ - 3 Cot θ - Cot θ+ √3 = 0br /br /⇒ √3 Cot θ( Cot θ  - √3)  - 1( Cot θ - √3)  = 0br /br /⇒ ( Cot θ  - √3)(√3 Cot θ - 1) = 0br /br /Cot θ = √3  and  Cot θ = 1 / √3 .br /br /let Cot θ = √3 and Tan θ = 1 / √3 .br /br /Now Cot2θ +Tan2θ = 3 + 1 / 3 = 10 / 3.

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