the displacement of a particle executing SHM is given by y=0.25sin200t cm. the maximum speed of the particle is (a) 200 cm/s (b) 100 cm/s (c) 50 cm/s (d) 5.25 cm/s
plz answer it with the complete sol
- Ekta
- 20 मई
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8 उत्तर
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option C0Modal content
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max.speed=Amplitude*angular speed
given equation:Y=0.25sin200t cm
Y= A sin wt cm
So,A=0.25 cm;w=200 rad/s
max.speed=A*w=0.25*200=50cm/s
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500Modal content
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50cm|/s1Modal content
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c1Modal content
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The max speed of particle can be +-rw and equation is y=rsinwt. hence 0.25×200=505Modal content
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