the displacement of a particle executing SHM is given by y=0.25sin200t cm. the maximum speed of the particle is (a) 200 cm/s (b) 100 cm/s (c) 50 cm/s (d) 5.25 cm/s

plz answer it with the complete sol

Ekta
20 May
8 Answers

8 Answers

- JS
  
  Jyoti
- 20 May
option C
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- NS
  
  Niveditha
- 20 May
max.speed=Amplitude*angular speed
given equation:Y=0.25sin200t cm
Y= A sin wt cm
So,A=0.25 cm;w=200 rad/s
max.speed=A*w=0.25*200=50cm/s
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- DM
  
  Desai
- 20 May
50
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- SA
  
  Sasipreethi
- 18 May
50cm|/s
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desai

desai

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- SK
  
  Subhashini
- 18 May
50
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desai

desai

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- CV
  
  Chinnapogula
- 11 May
c
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desai

desai

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- Guninder
- 10 May
The max speed of particle can be +-rw and equation is y=rsinwt. hence 0.25×200=50
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desai

katherashala

aisha

rati

rakesh

desai

katherashala

aisha

rati

rakesh

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- RR
  
  Rahul
- 10 May
c
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desai

aryan

desai

aryan

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