plz someone answer this question with explanation If n is 6 and m is 0. Find maximum p electrons.
Atomic structure
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for n=6 and p orbital it would be 6p abd it has 3 orbitals of m=0 m=1 m=-1 hence in m=0 there can be max 2e-
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OK just go through electronic configuration. 2p,3p,4p,5p can be found before n=6&l=0 that is 6s. so 4 p orbitals of each contains 6electron,so 4*6=24
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6p k acc. M=0 so 1 suborbital can accommodate 2 elec-, but 6p hi ku le 6s bhi to hoskta h