Answer this question.. HCL question
A man and his son planned to paint their own house. The man alone can do in 20 days. He paints for 4 days and then his son completed in 8 days. Find how many days will they take working together? a) 12 days b) 11 days c) 7 days d) 8 days
- 2747 दृश्य
- 5 उत्तर
-
-
Nikhil
- 18 जनवरी
- 0 टिप्पणी
-
-
It is easy one.br /br / Answer is option strong(/strongstrongc) 7 days/strongbr /strongExplanation:/strongbr /Man's 1 day work = 1/20br /Then 4 days work = 4/20 = 1/5br /Remaining work = 1 - 1/5 = 4/5br /Now, 4/5 work is done by the son in 8 days.br /Then, whole work will be done by him in (8 x 5/4) days = 10 days.br /Then his 1 day work = 1/10br /The man and his son's 1 day work = 1/10 + 1/10 = 3/10br /They will complete the work together in 20/3 days = 6 2/3 days = 7 days(nearly).br /Hence the answer is 7 days.
-
Shreya
- 14 जून
- 0 टिप्पणी
-
- HCL PLACEMENT PAPERS - Preparation Tips ,Tricks ,Cracks ,Dos & Don's ?
- Qualification details?
- Where can I find some good books for HCL?
- HCL PLACEMENT PAPERS - PREVIOUS YEAR PAPERS, LAST YEAR PAPER?
- HCL PLACEMENT PAPERS - About,Minimum education qualification, job profile?
- Who is CEO of HCL? Who is the owner of HCL?
- What is HCL Infosystems? Explain your answer
- Please provide the details of SAT exam in HCL?
- HCl TSS Preparation guide?
- Please share some technical questions as well.
Man takes 20days alone so for 4 days, he will do 1/5 work. Left work will be 4/5 which the son does in 8 days, so, alone, boy takes 10 days and together, they will take 1/10 + 1/20 days, that is 7 days.