Answer this question.. HCL question
A man and his son planned to paint their own house. The man alone can do in 20 days. He paints for 4 days and then his son completed in 8 days. Find how many days will they take working together? a) 12 days b) 11 days c) 7 days d) 8 days
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Nikhil
- 18 Jan
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It is easy one.br /br / Answer is option strong(/strongstrongc) 7 days/strongbr /strongExplanation:/strongbr /Man's 1 day work = 1/20br /Then 4 days work = 4/20 = 1/5br /Remaining work = 1 - 1/5 = 4/5br /Now, 4/5 work is done by the son in 8 days.br /Then, whole work will be done by him in (8 x 5/4) days = 10 days.br /Then his 1 day work = 1/10br /The man and his son's 1 day work = 1/10 + 1/10 = 3/10br /They will complete the work together in 20/3 days = 6 2/3 days = 7 days(nearly).br /Hence the answer is 7 days.
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Shreya
- 14 Jun
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Man takes 20days alone so for 4 days, he will do 1/5 work. Left work will be 4/5 which the son does in 8 days, so, alone, boy takes 10 days and together, they will take 1/10 + 1/20 days, that is 7 days.