At a particular locus frequency of allele A is 0.6 and that of allele a is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium
pls ans with explaination
- Prangyaparamita
- 07 Nov
- 3 Answers
3 Answers
3 Answers
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Accordingly to Hardy-Wienberg principle, P² + 2PQ + Q² = 1 , where P and Q are the individual frequency of dominant amd recessive allele respectively at a particular locus and the term 2PQ represents the frequency of heterozygotes in a randomly mating population. Hence, the answer should be (2*0.6*0.4) = 0.48 .0Modal content
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the frequency remains constant at equilibrium0Modal content
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0.480Modal content
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