pls ans with explaination
Accordingly to Hardy-Wienberg principle, P² + 2PQ + Q² = 1 , where P and Q are the individual frequency of dominant amd recessive allele respectively at a particular locus and the term 2PQ represents the frequency of heterozygotes in a randomly mating population. Hence, the answer should be (2*0.6*0.4) = 0.48 .