if t^2+100=4vt then find the possible values of v

mechanics

• Bhavya
• 2895 Views
• 1 Answers

• We solve this equation for v:br /br /4vt=100+t^2, v=(100+t^2)/4t.br /br /Now, to the possible values.br /br /We cant calculate v when t=0 (divizion by 0). Also, t can not be negative, so v too. Then we find the minimum for v(t).br /br /br /br /v^2;(t)=-25/t^2+1/4=0 so t=10 is a local minimum.br /br /Minimal value for v is v(10)=(100+100)/40=5m/s maximum is any.br /br /So the answer - v is equal or greater than 5 m/s.

  • Shruti
  • 02 Apr
  • 0 Comment

  0

  ---

• How to cover general knowledge for AIIMS or which book is good for preparation of Gk to appear in AIIMS 2018?
• anthrozoids are large enough to be seen by naked eye are produced in
• which book should i prefer for physics??
• how we find op from dpd
• what is calmodulin
• give TIPS AND TRICKS to crack AIIMS examination
• order for melting $ boilong point
• schik test is for which disease?
• preparation for neet and aiims
• Aiims exam question