-
-
- 14 Jul
- 0 Comment
-
-
entropy and temperature are directly proportional to each other.br /ds=dq/dt.br / br /The same amount of additional heatwill cause different amount of change in entropy.
-
- 14 Jul
- 0 Comment
-
-
The formula is actually better writtenbr /ΔS=Q/T.br /That is, the strongchange/strong in entropy associated with the flow of heat is inversely proportional to the temperature at which the heat flow occurs. Note that Q is already a change itself: it is not a state variable, but rather something more like ΔW. Physically, this is because adding heat to a hot system doesn't disorder it as much as adding the same heat to a cold system.If T is changing, you would need to integratebr /ΔS=∫dS=∫δQ/Tbr /For an ideal gas at constant volume and particle number, it turns outbr /ΔS∝log(Tfinal / Tinitial).br /Thus doubling the temperature does lead to the exponential of S doubling, as you would expect.
-
- 01 Jul
- 0 Comment
-
- JEE Advanced 2018 Exam, JEE advanced application form
- How to Prepare for JEE advanced? Any Study Material available?
- What is the eligibility for JEE Advanced?
- JEE Advanced 2018 Exam, JEE advanced eligibility 2018
- Which study material is best for IIT JEE exam?
- What is the last date to apply for JEE Advanced Exam?
- What is the Syllabus of JEE Advanced Exam ??
- What is the JEE Advanced? Explain your answer
- Joint Entrance Examination, JEE (Advanced) 2018, jee advanced prep
- JEE Advanced Exam Question
We know thatbr /∆S=- ∆q\Tbr /The above relationship show thatbr /Entropy is direcialy proportional to temperature,br /2nd law of thermodynamic prove this relationship also