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Let A Denote the set of positive integers, each of them whrn divided bu 2,3,4,5 and 6 leaves the remainder of1,2,3,4 & 5 respectively. How many numbers in A are between 0 & 100

solve please

  • Dharender
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  • 3 Answers
  Answer
3 Answers

  • Lcm(2,3,4,5,6)-1= 60-1=59

    0

  • the required number is given by = LCM(2,3,4,5,6) - 1 = 60-1 = 59

    0

  • Since the difference between the divisor and the remainder in each case is 1. So the required number is given by = LCM(2,3,4,5,6) - 1 br /= 60-1br /= 59

    0
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