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Mindtree question from quant section. Plz answer?

Qus. Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them? A. 42, 33 B. 42, 36 C. 44, 33 D. 44, 36

  • Vishal
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  • 3 Answers
3 Answers
  • Alternative trick is just check the option given 42-33=9 42-36=6 44-33=10 44-36=8 Answer is first option


  • Answer is Option strongA 42,33/strong


  • strongAnswer:/strong Option Abr /strongExplanation:/strongbr /Let the marks secured by them be xx and (x+9)(x+9)br /br /sum of their marks =x + (x+9)br / = 2x+9br /=x+(x+9)br /=2x+9br /br /Given that (x+9)(x+9) was 56% of the sum of their marks.br /⇒(x+9)br /=56100(2x+9)⇒(x+9)=1425(2x+9)⇒25x+225=28x+126⇒3x=99⇒x=33⇒(x+9)=56100(2x+9)⇒(x+9)=1425(2x+9)⇒25x+225=28x+126⇒3x=99⇒x=33br /br /Then (x+9)=33+9=42(x+9)=33+9=42br /br /Hence their marks are 33 and 42


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