the displacement of a particle executing SHM is given by y=0.25sin200t cm. the maximum speed of the particle is (a) 200 cm/s (b) 100 cm/s (c) 50 cm/s (d) 5.25 cm/s

plz answer it with the complete sol

• Ekta
• 8505 查看
• 8 答案

• option C

  • Jyoti
  • 20 5月
  • 0 评论

  0

  ---

• max.speed=Amplitude*angular speedbr /given equation:Y=0.25sin200t cmbr /                          Y=  A sin  wt   cmbr /So,A=0.25 cm;w=200 rad/sbr /max.speed=A*w=0.25*200=50cm/sbr / 

  • Niveditha
  • 20 5月
  • 0 评论

  0

  ---

• 50

  • Desai
  • 20 5月
  • 0 评论

  0

  ---

• 50cm|/s

  • Sasipreethi
  • 18 5月
  • 0 评论

  1

  ---

• 50

  • Subhashini
  • 18 5月
  • 0 评论

  1

  ---

• c

  • Chinnapogula
  • 11 5月
  • 0 评论

  1

  ---

• The max speed of particle can be +-rw and equation is y=rsinwt. hence 0.25×200=50

  • Guninder
  • 10 5月
  • 0 评论

  5

  ---

• c

  • Rahul
  • 10 5月
  • 1 评论

  2

  ---

• what would be the best preparation for aiims.will cbse books be good?
• Is there only online process for submit fees?
• is the NEET 2017 will reconduct
• iska koi Hindi version btyega plzzz
• is ncert bio is sufficient for aiims
• how to study for neet for me from nepal2017
• kindli solve this 25x²+x-90=0
• when will be Neet forms out ?
• Is ncert with MTG 29 years are sufficient for neet
• which topics are most important for AIIMS in chemistry