the displacement of a particle executing SHM is given by y=0.25sin200t cm. the maximum speed of the particle is (a) 200 cm/s (b) 100 cm/s (c) 50 cm/s (d) 5.25 cm/s

plz answer it with the complete sol

• Ekta
• 7840 दृश्य
• 8 उत्तर

• option C

  • Jyoti
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• max.speed=Amplitude*angular speedbr /given equation:Y=0.25sin200t cmbr /                          Y=  A sin  wt   cmbr /So,A=0.25 cm;w=200 rad/sbr /max.speed=A*w=0.25*200=50cm/sbr / 

  • Niveditha
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• 50

  • Desai
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  0

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• 50cm|/s

  • Sasipreethi
  • 18 मई
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• 50

  • Subhashini
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• c

  • Chinnapogula
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• The max speed of particle can be +-rw and equation is y=rsinwt. hence 0.25×200=50

  • Guninder
  • 10 मई
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• c

  • Rahul
  • 10 मई
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