the displacement of a particle executing SHM is given by y=0.25sin200t cm. the maximum speed of the particle is (a) 200 cm/s (b) 100 cm/s (c) 50 cm/s (d) 5.25 cm/s

plz answer it with the complete sol

  • Ekta Sheoran Ekta
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8 Answers

  • option C

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  • max.speed=Amplitude*angular speedbr /given equation:Y=0.25sin200t cmbr /                          Y=  A sin  wt   cmbr /So,A=0.25 cm;w=200 rad/sbr /max.speed=A*w=0.25*200=50cm/sbr / 

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  • 50

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  • 50cm|/s

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  • 50

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  • c

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  • The max speed of particle can be +-rw and equation is y=rsinwt. hence 0.25×200=50

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  • c

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