the displacement of a particle executing SHM is given by y=0.25sin200t cm. the maximum speed of the particle is (a) 200 cm/s (b) 100 cm/s (c) 50 cm/s (d) 5.25 cm/s
plz answer it with the complete sol
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8 Answers
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- 20 May
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max.speed=Amplitude*angular speedbr /given equation:Y=0.25sin200t cmbr / Y= A sin wt cmbr /So,A=0.25 cm;w=200 rad/sbr /max.speed=A*w=0.25*200=50cm/sbr /
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- 20 May
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The max speed of particle can be +-rw and equation is y=rsinwt. hence 0.25×200=50
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- 10 May
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